2(2y^2-8y+6)-4(3y^2-4y+2)=

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Solution for 2(2y^2-8y+6)-4(3y^2-4y+2)= equation: 


Simplifying
2(2y2 + -8y + 6) + -4(3y2 + -4y + 2) = 0

Reorder the terms:
2(6 + -8y + 2y2) + -4(3y2 + -4y + 2) = 0
(6 * 2 + -8y * 2 + 2y2 * 2) + -4(3y2 + -4y + 2) = 0
(12 + -16y + 4y2) + -4(3y2 + -4y + 2) = 0

Reorder the terms:
12 + -16y + 4y2 + -4(2 + -4y + 3y2) = 0
12 + -16y + 4y2 + (2 * -4 + -4y * -4 + 3y2 * -4) = 0
12 + -16y + 4y2 + (-8 + 16y + -12y2) = 0

Reorder the terms:
12 + -8 + -16y + 16y + 4y2 + -12y2 = 0

Combine like terms: 12 + -8 = 4
4 + -16y + 16y + 4y2 + -12y2 = 0

Combine like terms: -16y + 16y = 0
4 + 0 + 4y2 + -12y2 = 0
4 + 4y2 + -12y2 = 0

Combine like terms: 4y2 + -12y2 = -8y2
4 + -8y2 = 0

Solving
4 + -8y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -8y2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -8y2 = 0 + -4
-8y2 = 0 + -4

Combine like terms: 0 + -4 = -4
-8y2 = -4

Divide each side by '-8'.
y2 = 0.5

Simplifying
y2 = 0.5

Take the square root of each side:
y = {-0.707106781, 0.707106781}

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